A pendulum of length 2 m is vibrating on a planet. It completes one vibration in 5 seconds. What is the value of gravitational acceleration on this planet?
3. Gravitational acceleration on a planet: Given: Length of pendulum L=2 m Time period T=5 s. Using the formula for the time period: T=2π√L/g Rearranging for g: g=4π2L/T2 Substitute the given values: g=4π2×2/5 g≈4×9.87×2/25 g≈2.51m/s2 Related Questions: A simple pendulum has a time period of 2 s. It is called a second pendulum. Find the length of … Read more