Statements:
1. Write the following numbers in scientific notation:
a. 1234 m b. 0.000023 s c. 469.3 × 10⁷ m d. 0.00985 × 10⁵ s
2. Express the following measurements using prefixes:
a. 27.5 × 10⁶ m b. 0.00023 × 10⁹ s
3. If a boy is 15 years, 2 months, and 10 days old, convert his age into:
a. Seconds b. Milliseconds c. Megaseconds
4. How many kilometers are there in 25 micrometers?
5. What is the pitch and least count of:
a. Vernier calipers if the smallest division on the main scale is 1 mm and the vernier scale has 20 divisions.
b. Screw gauge if the smallest division on its main scale is 0.5 mm and its movable scale has 50 divisions.
1. Write the following numbers in scientific notation:
a. 1234 m
- 1234= 1.234×103 meters
b. 0.000023 s
- 0.000023=2.3×10−5
c. 469.3 × 10⁷ m
- 469.3×107=4.693×109 meters
d. 0.00985 × 10⁵ s
- 0.00985×105=9.85×101 seconds
2. Express the following measurements using prefixes:
a. 27.5 × 10⁶ m
- 27.5×106 m=27.5 Mm (megameters)
b. 0.00023 × 10⁹ s
- 0.00023×109 s=230 ms (milliseconds)
3. If a boy is 15 years, 2 months, and 10 days old, convert his age into:
a. Seconds
- 1 year = 365 days (not accounting for leap years)
- 1 month = 30 days (approx.)
- 1 day = 24 hours = 86400 seconds
Total age in seconds:
- 15 years×365 days/year×86400 seconds/day
- 2 months×30 days/month×86400 seconds/day
- 10 days×86400 seconds/day
Total age in seconds:
- 473385600+5184000+864000=479019600 seconds
b. Milliseconds
- Since 1 second = 1000 milliseconds, multiply the seconds result by 1000.
Boy’s Age:
- 479019600×1000=479019600000 milliseconds
c. Megaseconds
- Since 1 megasecond = 106 seconds, divide the total seconds by 106
Boy’s age:
- 479019600÷106=479.02 megaseconds
4. Converting 25 micrometers to kilometers:
- 25 μm=25×10−6 m=25×10−9 km=0.000000025 km
So, there are 0.000000025 kilometers in 25 micrometers.
5. What is the pitch and least count of:
a. Vernier calipers
- Smallest division on the main scale = 1 mm = 0.1 cm
- Vernier scale has 20 divisions, so pitch = 1 mm/20=0.05 mm.
The least count = Pitch = 0.05 mm.
b. Screw gauge
- Smallest division on the main scale = 0.5 mm
- Movable scale has 50 divisions, so pitch = 0.5 mm/50=0.01 mm.
The least count = Pitch = 0.01 mm.
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- Q.2 Estimate your age in minutes and seconds.
- Q.3 What base quantities are involved in these derived physical quantities; force, pressure, power and charge.
- Q.4 Show that prefix micro is thousand times smaller than prefix milli.
- Q5. Justify that displacement is a vector quantity while energy is a scalar quantity.
- Q6. Screw gauge can give more precise length than vernier calipers. Briefly explain why?
- Q.7 Differentiate between Mechanical Stopwatch and Digital Stopwatch.
- Q.8 How measuring cylinder is used to measure the volume of an irregularly shaped stone?
- Q.9 What precautions should be kept in mind while taking measurements using a measuring cylinder?
- Q.10 Why do we need to consider significant digits in measurements?
- Q11. How random error can be reduced?
- Q12. Differentiate between precision and accuracy.
- Q.1 Define Physics. Describe its revolutionary role in technology.
- Q2. List with brief descriptions of different branches of physics.