The formation of sodium chloride (NaCl) can be explained using electron dot structures:
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Step 1: Sodium (Na), an alkali metal, has one electron in its outermost shell (1s² 2s² 2p⁶ 3s¹). Chlorine (Cl), a halogen, has seven electrons in its outermost shell (1s² 2s² 2p⁶ 3s² 3p⁵).
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Step 2: Sodium donates its single valence electron to chlorine, forming a Na⁺ ion (positively charged) and a Cl⁻ ion (negatively charged).
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Na: Na → Na⁺ + e⁻ (Electron dot structure: Na → [Na]⁺)
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Cl: Cl + e⁻ → Cl⁻ (Electron dot structure: Cl: [Cl]⁻)
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Step 3: The electron transfer results in the formation of oppositely charged ions, Na⁺ and Cl⁻. These ions are held together by electrostatic attraction, forming an ionic bond and resulting in the compound NaCl.