According to the equation of capacitance of a capacitor, capacitance is numerically equal to the ratio between the charge stored on one of its plates and the potential difference between its plates. Does its value depend on the amount of charge and potential difference?

The capacitance of a capacitor, according to the equation C=Q/V, where C is the capacitance, $Q$ is the charge stored on one of its plates, and $V$ is the potential difference between the plates, does not depend on the amount of charge $Q$ or the potential difference $V$.

Instead, capacitance is a property of the capacitor itself and depends on factors such as:

1. The area of the plates: Larger plate area provides more surface area to store charge, increasing capacitance.
2. The distance between the plates: A smaller distance between the plates increases the capacitance.
3. The dielectric material between the plates: A material with a higher dielectric constant (also called permittivity) increases the capacitance.

So, while the charge and voltage are related to how much energy is stored in the capacitor, the capacitance is determined by the physical characteristics of the capacitor and is constant for a given configuration.

In summary, capacitance is independent of the charge Q and potential difference $V$; it only depends on the geometry and the dielectric material of the capacitor.