Output of the program:
#include <stdio.h>
void main(void) {
int b;
float a, c, d, e, f;
a = 14.84;
b = 7;
c = a – b;
printf(“\nc=%f”, c); // c = 14.84 – 7 = 7.840000
d = a / b;
printf(“\nd=%f”, d); // d = 14.84 / 7 = 2.120000
e = a – b * 3;
printf(“\ne=%f”, e); // e = 14.84 – 21 = -6.160000
f = (a + b) * 2;
printf(“\nf=%f”, f); // f = (14.84 + 7) * 2 = 21.680000
}
Output:
c=7.840000
d=2.120000
e=-6.160000
f=21.680000