3. Gravitational acceleration on a planet:
Given:
- Length of pendulum L=2 m
- Time period T=5 s.
Using the formula for the time period:
T=2π√L/g
Rearranging for g:
g=4π2L/T2
Substitute the given values:
g=4π2×2/5
g≈4×9.87×2/25
g≈2.51m/s2
Related Questions:
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